>From the datasheet, it looks like Vout(max) is Vdd-25 mV (at Vdd=3D 5V5) a= nd that is with 0.5 V input overdrive. Vout(min) is Vss +25 mV. *IF* these still hold at Vdd =3D 5 V, then the *BEST* to expect is 4.95 p-p. - no margin there. Also, there is dependence on output load, as shown in Fig 2.14. As for rounding, there is often a loss of linearity for R-R op-amps the closer you get to the supply rails (both). Also, the input capacitance will limit the sharpness. This last you can model from the datasheet values for input impedance. You don't mention your load or gain. These will be critical - your frequency is fine but I think you might struggle to get a "sharp" triangle with the supply and output conditions you desire. How much distortion can you tolerate? On Fri, Jun 7, 2019 at 6:41 AM Jason White < whitewaterssoftwareinfo@gmail.com> wrote: > The supply rail is 5V. The actual peak to peak voltage of the triangle > wave is (hoped) to be about 4.95V. > > On Thu, Jun 6, 2019 at 4:34 PM Richard Prosser > wrote: > > > > Hi Jason > > Looks like your calculations check out OK. > > I've never seen 2nd order slew rate specified - but you could check > > distortion figures, if they're available. > > As far as rounding goes, I'd look at a simulation package or even set u= p > a > > spreadsheet type approach if it's critical. > > > > Re the actual figure - what supply rail are you running? Slew rate > > typically applies in the small signal linear region and if youre trying > for > > 5V pk-pk on a 5V supply you will probably have issues. There may be a > > difference between large (>20% supply ?) & small signal (<5% ?) rates. > > > > RP > > > > On Fri, 7 Jun 2019 at 07:31, Jason White < > whitewaterssoftwareinfo@gmail.com> > > wrote: > > > > > Hello PICLIST, > > > > > > I am looking for a sanity check. > > > > > > The MCP6001 has a published minimum slew rate of at least 0.4V/us at > > > 5V and -40C. 0.4V/us=3D400kV/s. > > > > > > In my application I am generating a 5V pk-pk 25kHz triangle wave. The > > > slew rate of a 25kHz triangle wave voltage rise V over time t. For > > > slew rate the time would be 1/2 the period of the triangle wave or > > > 1/2*1/25kHz=3D20us, the rise would be 5V. 5V/20us=3D250kV/S=3D0.25V/u= s > > > > > > According to this the required slew rate for the triangle wave is > > > 0.25V/us which is within the 0.4V/us limit. > > > > > > Four questions: > > > * Does the slew rate calculation given above "check out" ? > > > * Slew rate is rate of change (the first derivative) of the output. > > > Are op-amps ever rated for rate of rate of change (second derivative) > > > of the output? > > > * Is there a way to deduce how much rounding will occur on the sharp > > > points of the triangle wave from the MCP6001 ratings? > > > > > > -- > > > Jason White > > > -- > > > http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive > > > View/change your membership options at > > > http://mailman.mit.edu/mailman/listinfo/piclist > > > > > -- > > http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive > > View/change your membership options at > > http://mailman.mit.edu/mailman/listinfo/piclist > > > > -- > Jason White > -- > http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive > View/change your membership options at > http://mailman.mit.edu/mailman/listinfo/piclist > --=20 http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist .