I'm designing this shift register into a small volume product but am=20
wondering about one aspect of its operation.

It has a VDD pin (10.8 - 13.2V) for the logic side and a VPP pin (8.0V -=20
80V) for the output switching side.

They have this in the data sheet:

> To power-up HV5308 / HV5408, perform the following
> power-up sequence:
> 1. Connect ground
> 2. Apply VDD
> 3. Set all inputs (Data, CLK, LE, etc.) to a known
> state
> 4. Apply VPP
> 5. The VPP should not fall below VDD or float during
> operation.
> To power-down the device, reverse the steps above.

Now, I'm actually using the same 12V supply for both VDD and VPP. Do you=20
think I really need to worry about the power sequencing?

I'm thinking no, because VPP will never be able to fall below VDD. Thoughts=
?
David...

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___________________________________________
David Duffy        Audio Visual Devices P/L
Unit 8, 10 Hook St, Capalaba 4157 Australia
Ph: +61 7 38235717      Fax: +61 7 38234717
Our Web Site: www.audiovisualdevices.com.au
___________________________________________

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