Hello, this is for an extremely space-constrained application, so every component counts. The PIC datasheet specifies what is the max current that can be sourced/sin= ked by a PIC pin. However, this in principle means that no capacitance can be directly driven= , as any capacitor with low ESR (eg. ceramic) will look almost like a short circuit, although only for a very brief time. Regardless of what the datasheet strictly says, in your experience is it sa= fe to drive a 10nF capacitance directly from a PIC pin (for few hundreds Hz's, i.e. without thermal or average current excesses, only peak current), or a resistor is always needed? The internal resistance of the pin is in the tens of ohms already, so I won= der. While the peak current, without the external resistor, will exceed the maxi= mum specified in the datasheet, this is meant as "continuous current", while MO= SFETs do always exhibit a higher peak current capability.. so why not also PIC pi= ns? Thank you for your insights. Kind regards, Mario --=20 http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist .