Hi Brent, > Hi Jim, > > When the load is shorted, yes the power supply is now directly connected = across > Drain/Source of the FET, but no, VDS will not be 24V. The FET is in the o= n state > (around 9 milli Ohms) and the power supply will hit it's current limit of= 25A. > Therefore VDS is around 0.009 x 25 =3D 225mV. Power dissipation in the FE= T is > 0.225 x 25 =3D 5.6W, well within the FETs safe operating area - for the m= oment. > > Just to check that VDS can not be 24V, that would require 24 / 0.009 =3D = 2667A. > While brief duration high current peaks might occur if there were suffici= ent > capacitance on the output of the supply, and the FET would be destroyed, = that's > likely not the case here given the supply is characterised for use in con= stant current > mode. > > The failure mechanism is probably what occurs a short time later. As the = supply has > been shorted (0.225V) then whatever circuitry is driving the FET gate has= also lost > power and the gate voltage begins to drop (relatively slowly as there'll = be some > capacitance in the drive electronics eg. could be some seconds or so, and > assuming there are no effective under voltage lock out schemes in place a= nd > seems likely in this case there are none). The FET begins to come out of = saturation > (into the linear region ie the state between on and off) and RDS increase= s. IDS > stays the same (external supply still happily current limits at 25A) so p= ower > dissipation in the FET increases proportionally with RDS, junction temper= ature rises > at an exponential rate and very soon the FET melts and is destroyed. Can = do some > I2R at a few data points to illustrate: > > 25^2 x 0.009 =3D 5.6W > 25^2 x 0.05 =3D 31W > 25^2 x 0.1 =3D 63W > 25^2 x 0.2 =3D 125W > 25^2 x 0.5 =3D 313W > 24^2 x 1.0 =3D 576W > 12^2 x 2.0 =3D 288W > > Note: Supply comes out of current limiting above max power point of R = =3D 0.96 > Ohms (24V/25A) and power declines beyond that, but dissipation still very= high and > depending on time-frame SOA likely well and truly exceeded and meltdown a= lready > acheived. > > Ideally: Under voltage lockout circuit to keep FET off when there insuffi= cient gate > voltage - but you're unable to modify the drive circuitry in your case. > > Plan B: Separate external supply for driver circuit to keep it working wh= en main > supply drops due to short. RDS stays low, current limits at 25A, lights g= o out, short > is removed, lights back on again - everyone is happy~! > > Hope this helps. Super helpful, so awesome of you to take the time to answer this so=20 completely. It had slipped my mind that the current limiting would kick=20 in forcing the voltage to drop on the power supply. Hopefully next week=20 I will get my hands on this unit and see what happens if the driver has=20 a secondary supply. Cheers, Jim > > --=20 http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist .