At 02:34 PM 11/29/2015, you wrote: >Cheap log pots, according to my measurements, are two linear sections. = 0 >- R/10 at half rotation and R/10 to R at full rotation. That leads to a >very noticeable and disturbing discontinuity around the mid point. >I also often wonder why they are called "log" pots when their law is >actually exponential? You'd normally use it as a voltage divider, With your R0/10 at 0.5 rotation (other curves such as R0/5 @ 0.5 rotation are available), the ideal exponential equation for the resistance R to the CCW terminal is: R =3D (1/80) R0 * (exp(k * a) - 1) where 0<=3Da<1 is the pot rotation and k =3D ln(81) ~=3D 4.39 is a constant. So, the output ratio of R/R0 .. the voltage you'd get with a voltage divide= r.. is (sort of) logarithmic with wiper position a: ln((R/R0)*80) =3D k * a -1 --sp --=20 http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist .