On Tue, Mar 24, 2015 at 3:32 PM, Sergey A Dryga <sergey@dryga.us> wrote:
> try:
> int32 tmp =3D encval;
> tmp =3D (tmp * 100) / 255;
> encper =3D tmp;
> When you make division first, you loose resolution, so any value <255 wil=
l
> be 0.
> if encval has range 0-655, then you do not need to use int32 temp variabl=
e.
>
> Hope this helps,

AHA! That did it. Next up I need to try the shifting method of division.

Thank you!

Josh
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