super! On Tue, Mar 17, 2015 at 8:30 PM, Mark Jordan wrote: > http://www.sengpielaudio.com/ohms-law-illustrated.gif > > Mark Jordan > > > On 17-Mar-15 14:43, embedded systems wrote: > > Not for me.... > If km/h equal voltage, as long the water has more resistance it should > create a higher voltage drop at the same current... > So, if air is 10Km/h, water should be more than 10km/h and not 5km/h... > > Let's try my version. Current (I) is represented by one ant. The copper > wire is an empty water pipe. The ants walks through the pipe. Resistance > (R) is the pipe diameter. Voltage (V) is the difference between the numbe= r > of ants at the pipe ends. As lower the pipe diameter (meaning as higher t= he > resistance), as many ants will stay on the pipe ends and only a few with > guts (a small current) will pass through the pipe. > :) > > > Vasile > -- > http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive > View/change your membership options at > http://mailman.mit.edu/mailman/listinfo/piclist > --=20 http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist .