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    Mark Jordan


On 17-Mar-15 14:43, embedded systems wrote:

Not for me....
If km/h equal voltage, as long the water has more resistance it should
create a higher voltage drop at the same current...
So, if air is 10Km/h, water should be more than 10km/h and not 5km/h...

Let's try my version. Current (I) is represented by one ant. The copper
wire is an empty water pipe. The ants walks through the pipe. Resistance
(R) is the pipe diameter. Voltage (V) is the difference between the number
of ants at the pipe ends. As lower the pipe diameter (meaning as higher the
resistance), as many ants will stay on the pipe ends and only a few with
guts (a small current) will pass through the pipe.
:)


Vasile
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