Hi Ryan, You are right! It does not increase the storage of the filter capacitor. If you have an unregulated power supply with a filter capacitor (an old-school DC wall-wart, for example) there will be ripple under load. The greater the load, the greater the ripple. What the described circuit can do (with appropriate transistor/resistor/capacitor choices) is maintain the output voltage a little under the lowest peak of the ripple. The ripple on the output is less than, but follows, a multiple of the circuit's capacitor. The nice thing about it is that the output voltage drops with load, so it almost tracks the lower ripple peak, something a 78xx regulator can't do. It also has less insertion loss. Cheerful regards, Bob On Thu, Mar 5, 2015, at 06:50 PM, Ryan O'Connor wrote: > That page is really informative. However, I'm left wondering about the > physics. How can a capacitor which stores charge possibly be "multiplied" > without any additional storage? >=20 > Ryan >=20 > On 6 March 2015 at 02:46, Adam Field wrote: >=20 > > On Wed, Mar 4, 2015 at 12:17 PM, Bob Blick wrote: > > > Hi Joe, > > > You could use a one transistor pass element to multiply a capacitor. = Let > > > me see if I can find an example on the web... nope. here's napkin art= .. > > > > > > Bob > > > > ESP has a good page on the concept: > > > > http://sound.westhost.com/project15.htm --=20 http://www.fastmail.com - Access all of your messages and folders wherever you are --=20 http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist .