It can't, it is a simple linear regulator (an emitter follower) whose output follows the capacitor's voltage. What it does is maintain a smooth output voltage while allowing large surges of current to pass through the transistor, making it appear as if there was a much larger filter capacitor hooked up to the "regulated" rail. AFAIK, The term "capacitance multiplier" applies more to the fact that the output of the transistor follows the output of a RC filter, using a large values R makes the RC time constant longer leading to more smoothing on the output. The RC filter responds many times slower than a simple capacitor making it appear as if a much larger one was at work. On Thu, Mar 5, 2015 at 9:50 PM, Ryan O'Connor wrote: > That page is really informative. However, I'm left wondering about the > physics. How can a capacitor which stores charge possibly be "multiplied" > without any additional storage? > > Ryan > > On 6 March 2015 at 02:46, Adam Field wrote: > >> On Wed, Mar 4, 2015 at 12:17 PM, Bob Blick wrote: >> > Hi Joe, >> > You could use a one transistor pass element to multiply a capacitor. L= et >> > me see if I can find an example on the web... nope. here's napkin art. >> > >> > Bob >> >> ESP has a good page on the concept: >> >> http://sound.westhost.com/project15.htm >> -- >> http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive >> View/change your membership options at >> http://mailman.mit.edu/mailman/listinfo/piclist >> > -- > http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive > View/change your membership options at > http://mailman.mit.edu/mailman/listinfo/piclist --=20 Jason White --=20 http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist .