Hello,
suppose we have a capacitor made of 2 armatures and a dielectric.
Like two rigid sheets of metal with a sheet of paper in between.

We begin with the capacitor assembled, i.e. with the two armatures
closely together (and the dielectric in the middle).

Now we also charge the capacitor.

We measure tension between the two terminals, but we leave the
capacitor charged.

Now we separe the two armatures, placing them apart, very distant
from each other.

My question is: will there still be a voltage accross the two
terminals?

I think I know the answer (NO) but I'd like to fully understand
at the intuitive level why. Ok it's the electric field between
the armatures that causes a difference of potential in the
terminals.. but why?
I mean, when I charged the capacitor, I effectively moved charges
from an armature and transferred them into the other. So why doesn't
the difference in potential remain?

Cheers,
Mario

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