Sqrt of zero equals to zero, it is not a special case. The problem would
arise in the resulting division by zero.



On 22/11/2014 16:23, alan.b.pearce@stfc.ac.uk wrote:
>> Relativistic mass increase is given by M =3D M_rest /sqrt(C^2-V^2) This =
of
>> course returns a divide by 0 at V=3DC and hence infinite mass.
> Doesn't it give sqrt() a problem first by attempting to take the sqrt of =
0?
>
> Seems to me there might have a kernel crash here as we do x/(sqrt(0). Doe=
s this cause the (single) universe to implode?

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