Jan=3DErik,
     I think I finally understand. I did this.
         Reset display;
         Turn the Gate on;
           call delay(numberseconds);  //This will be for one second
         Turn the Gate off;

         call delay(numberseconds); again  /This will be for 15 seconds.
         do forever

         delay(numberseconds)
         {
             for(count =3D 0; count <=3D numberseconds*10;);
             return;
         }

         interruptcode goes here.

         void Interrupt()
         {
             if (TMR1IF_bit)
                 {
                      TMR1IF_bit =3D 0;
                      TMR1H =3D 0x0B;
                      TMR1L =3D 0xDC;
                       count++; //This increments the count variable=20
which was declared as global.
                 }
          }

It compiles. Now I have to test it and see what the output is. If this work=
s I'll then add the pot and the ADC so that the display time can be varied.=
 I'm getting there.
Thanks,
rich!
P.S. Allen this also uses your suggestion.
Thanks,
rich!

On 7/19/2014 4:39 PM, Jan-Erik Soderholm wrote:
>   > Jan-Erik,
>   > The interrupt happens every 100mS. So for a one second delay I need
>   > to execute ten interrupts.
>
> No, that is done automaticly. You doesn't have to
> do anything, the 10 interrupts will happen each
> 1 second by the hardware.
>
>   > But I just don't understand how to do this.
>
> You don't have to do anything. Just let your interrupts
>

--=20
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