On 12 July 2013 05:06, electronic.consultation.au@gmail.com <
electronic.consultation.au@gmail.com> wrote:

> I see, and then how can I reduce them ?
>
> could it be like this ?
>
> *movlw LOW .300
>                  movwf LedTimer
>                  movlw HIGH .300
>                  movwf LedTimer+1
>
> counter* *
>           Global     counter            ;Decrementing Sec's
>           BANKSEL     LedTimer        ;timer value
> *           movf         LedTimer,w        ;for every counts
>           btfss         STATUS,Z    ***you do not need this*
>           decf       LedTimer,f
>
>           movf         LedTimer+1,w        ;for every counts
>           btfss         STATUS,*C    <-- carry, not zero*
>           decf       LedTimer+1,f
>           return*
>
> Thank you
> On 12/07/2013 7:36 PM, IVP wrote:
> > Tag added
> >
> >> how can I enter .300 into LedTimer ?
> > You might assign two registers, LedTimer_lo and LedTimer_hi
> >
> > The low( ) and high( ) operators do the division/remainder for you
> >
> > movlw  low(.300)  ;loads LedTimer_lo with 44
> > movwf  LedTimer_lo
> >
> > movlw  high(.300)  ;loads LedTimer_hi with 1
> > movwf  LedTimer_hi
> >
> > For 24-bit numbers this can be extended to
> >
> > movlw upper(.300)
> > movwf  LedTime_up  ;if LedTimer_up is also present
> >
> > If the 300 is defined as a constant, this makes it easier to change
> > in the following line rather than in the code
> >
> > LedTimer =3D .300
> >
> > movlw  low(LedTimer)
> > movwf  LedTimer_lo
> >
> > movlw  high(LedTimer)
> > movwf  LedTimer_hi
> >
> > A register LedTimer can also be addressed as LedTimer+0, the next
> > in memory as LedTimer+1 and so on, if that suits you better
> >
> > Joe
>
> --
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--=20
int main() { char *a,*s,*q; printf(s=3D"int main() { char *a,*s,*q;
printf(s=3D%s%s%s, q=3D%s%s%s%s,s,q,q,a=3D%s%s%s%s,q,q,q,a,a,q); }",
q=3D"\"",s,q,q,a=3D"\\",q,q,q,a,a,q); }
--=20
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