On Wed, Feb 6, 2013 at 4:16 PM, Sergey Dryga wrote: > Mark Rages gmail.com> writes: > >> You are measuring current upstream from the output transistors, so if >> you go BJT you will have error introduced by the base current, which >> will be added to the output current. The resultant error may be >> acceptable with Darlington outputs. >> > Would not the base current sourced by Vsupply, and, therefore not measure= d in > the collector current? This assumes that output transistor will be npn > connected as emitter follower, of course. Yes. Extra unmeasured current will be delivered to the load, introducing an error in constant-current mode. Regards, Mark markrages@gmail --=20 http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist .