> Shouldn't a GPS unit be able to determine the present time much more > quickly than a position fix? Sure, getting super-accurate (<<1sec) > time will require multiple satellites, but I would think that a single > satellite is all that is needed for a basic timestamp. I wondered about that when I wrote that post. That was partially what led to my 1=3D somewhere, 2 =3D torus, 3=3D 2 point= s comments - as Sean noted, as you get more satellites you initially get a shrinking locus of position and then from 4 up yopu get more accurate position BUT time data is present in every signal. Note though that while a typical GPS unit provides a 1 Hz square wave output, the accuracy of the edge timing of that square wave is awesome-accurate, and the awesomeness increases with position precision. When the system does not know where you are located it can give you standard time but not yopur local time. If you are stationary you can derive precise local time from std time (UTC) but it does not 'know' that you are able to do this. It's been "some years" since I played with GPS at the output analysis level, but I recall that the NEMA data indicates the number of satellites in a solution and a flag that says whether the data is considered valid or not. You start getting decipherable position output before it has enough satellites in use to be able to declare the result valid. Whether it does this with its time signal is tbd - and Google probably knows. A look through a dozen or so Gargoyle found documents which seemed most liable to help, didn't help. Results will depend on your receiver model. A receiver that gets UTC with one satellite may decide not to tell you so. Russell --=20 http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist .