In fact, how would the compiler interpret these two statements?

int *a, b;
int * c, d;

I'm pretty sure a is a pointer to int, b is an int, c is a pointer, but=20
not quite sure about d.

How about a struct typedef ?

typedef struct tag_fooT {
   int foo;
   char *s;
} fooT, *pfooT;

I know that declaring a fooT allocates space for the structure, and=20
declaring a pfooT allocates just the pointer as I do this all the time.

fooT fooStructA;
pfooT fooPointer =3D &fooStructA;


Joe W


On 9/29/2012 12:49 PM, Tamas Rudnai wrote:
> I prefer B, that is the most common -- plus as you have pointed out, with
> the 'int' you only told the compiler the base type, but with the '*' you
> are telling that this particular variable is a pointer type to that base
> type. So even if syntax allows you to do the way A, semantically it is
> still the way B.
>
> Tamas
>
>
> On 29 September 2012 09:17, V G <x.solarwind.x@gmail.com> wrote:
>
>> This is an opinion question. I am curious as to what you all think is a
>> good way to do this:
>>
>> In C/C++, what is your preferred way or declaring pointers?
>>
>> A) int*    p;
>> B) int    *p;
>> C) int  *  p;
>>
>> I think it should be A because it's logical and the C/C++ compiler
>> considersint*to be the type, and the syntax is<type> <identifier>;
>>
>> However, I see B a lot in code, and it doesn't make sense to me. Also,
>> function prototypes are usually written like so:
>>
>> void myFunction(int*, int*, char*); with the asterisk close to the type.
>>
>> Note that when doing this:
>>
>> int* x, y;
>>
>> Type type of x is int* whereas the type of y is int. To make the type of
>> both of them int*, one must do:
>>
>> int *x, *y;
>>
>> Apparently, the spaces get removed during compile time and it just becom=
es
>> int*x to the compiler.
>> *
>> Which way do you prefer?*
>> --
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>
>
>

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