I prefer B, that is the most common -- plus as you have pointed out, with
the 'int' you only told the compiler the base type, but with the '*' you
are telling that this particular variable is a pointer type to that base
type. So even if syntax allows you to do the way A, semantically it is
still the way B.

Tamas


On 29 September 2012 09:17, V G <x.solarwind.x@gmail.com> wrote:

> This is an opinion question. I am curious as to what you all think is a
> good way to do this:
>
> In C/C++, what is your preferred way or declaring pointers?
>
> A) int*    p;
> B) int    *p;
> C) int  *  p;
>
> I think it should be A because it's logical and the C/C++ compiler
> considersint*to be the type, and the syntax is<type> <identifier>;
>
> However, I see B a lot in code, and it doesn't make sense to me. Also,
> function prototypes are usually written like so:
>
> void myFunction(int*, int*, char*); with the asterisk close to the type.
>
> Note that when doing this:
>
> int* x, y;
>
> Type type of x is int* whereas the type of y is int. To make the type of
> both of them int*, one must do:
>
> int *x, *y;
>
> Apparently, the spaces get removed during compile time and it just become=
s
> int*x to the compiler.
> *
> Which way do you prefer?*
> --
> http://www.piclist.com PIC/SX FAQ & list archive
> View/change your membership options at
> http://mailman.mit.edu/mailman/listinfo/piclist
>



--=20
int main() { char *a,*s,*q; printf(s=3D"int main() { char *a,*s,*q;
printf(s=3D%s%s%s, q=3D%s%s%s%s,s,q,q,a=3D%s%s%s%s,q,q,q,a,a,q); }",
q=3D"\"",s,q,q,a=3D"\\",q,q,q,a,a,q); }
--=20
http://www.piclist.com PIC/SX FAQ & list archive
View/change your membership options at
http://mailman.mit.edu/mailman/listinfo/piclist
.