The instruction 'MOVF' has only room for 8 bits of the address. The
other bits are obtained from the BSR register.

So your "movf 0x240,w" will generate the exactly same binary encoding
than a "movf 0x40,w". I think the assembler will give a warning saying
that some bits of the address will be ignored (or at least it should).


Best regards,

Isaac




Em 29/8/2012 10:21, Nathan House escreveu:
> I'm learning to program a PIC18 using assembly language and am curious
> why there seems to be some redundancy with many instructions. Take the
> MOVF instruction, for example:
>
> MOVLB 0x2          ;select bank 2
> MOVF   0x240, W  ;move the value at 0x240 to W
>
> If my understanding is correct, then the "2" digit in the MOVF
> instruction is ignored completely, making it redundant since the bank
> is selected above. From what I've read, it seems that the assembler
> automatically sets the access "a" bit based on the address when
> translating to machine code, so what I'm wondering is why the
> assembler doesn't automatically generate bank select instructions as
> well?
>
> Thanks!
>
> Nathan
>

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