On Sun, Jul 1, 2012 at 5:44 PM, Vasile Surducan wrote: > Permittivity of a dielectric material can't be simulated (or it can > but is mostly useless). That's not correct. How can one determine anisotropic permittivity tensor of a heterogeneous material ? You can model your material and expose to various electric fields and measure the response in almost any computational electromagnetics platform. After a few iterations you will reach a significant precision. > It must be measured. You can't measure permittivity of gold or titanium for example, if you don't have very powerful high precision CNC. It highly depends on the material thus I think 'measuring' can't be a generic method. > Permittivity is frequency and temperature dependent. You have to > manufacture a capacitor from your dielectric and measure the capacity > at the requested frequency and voltage. From those two values, knowing > the relation between the sizes of a plane capacitor and it's value, > you may compute permittivity. > For dielectric strength you need a variable voltage supply up to > hundreds of KV and two electrodes with round shapes. Such devices > exists in HV laboratories. > > Vasile > http://www.itim-cj.ro/~vasile/ > > On Sun, Jul 1, 2012 at 4:40 PM, Yigit Turgut wrote: >> Permittivity, permeability and conductivity : these are the dielectric >> parameters of a material. >> >> You need to determine the permittivity of your material because this >> feature is what responds to electric fields. Unfortunately, it's not >> that easy to calculate precisely. What is your material ? Is it >> isotropic or anisotropic ? Does it respond linearly or non-linearly? >> All these questions rise from the fact the molecular structure of >> materials varies widely. You can't calculate it it but can do some >> simulations and have some acceptable approximations. >> >> On Sun, Jul 1, 2012 at 12:01 PM, Electron wrot= e: >>> >>> How do I calculate dielectric strenght of a material (i.e. V/mm until i= t breaks down >>> in a spark) given the dielectric constant and/or other required propert= ies (and which)? >>> >>> For example, for air (without humidity there to false the results, of c= ourse) I know it >>> is 1MV/m (1KV/mm), and ten times as much for epoxy.. but how is it calc= ulated? >>> >>> Thanks, >>> Mario >>> >>> -- >>> http://www.piclist.com PIC/SX FAQ & list archive >>> View/change your membership options at >>> http://mailman.mit.edu/mailman/listinfo/piclist >> -- >> http://www.piclist.com PIC/SX FAQ & list archive >> View/change your membership options at >> http://mailman.mit.edu/mailman/listinfo/piclist > -- > http://www.piclist.com PIC/SX FAQ & list archive > View/change your membership options at > http://mailman.mit.edu/mailman/listinfo/piclist --=20 http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist .