Capacitors: I'm trying to (fully) understand the principle of capacitor reactance and high pass filters. I'm having trouble forming a mental picture of how a capacitor in series with a signal blocks DC and has the lowest impedance for the highest frequency signals on a voltage and charge-on-the-plate level. I can understand how a capacitor tied to ground acts as a buffer and smoothes out high frequencies by averaging the voltage. But I don't really get how the reverse is true for a capacitor in series with a signal. I can see how it blocks DC after it is fully charged. 1. How does a capacitor in series work to block a DC signal, but pass a high frequency signal? 2. If you apply a voltage to a capacitor in series (keeping in mind that it takes time for the voltage from the power source to rise), I understand that the current before the capacitor is NON-zero. But what about the current AFTER (on the other side) of the capacitor? Is it zero or non-zero (considering that a capacitor is just two parallel plates)? LC circuits: 1. Consider a parallel LC circuit where the bottom is tied to ground and the top is tied to a mixed-frequency signal source. I understand that the parallel LC circuit will shunt all frequencies to ground other than those around its resonant frequency. After the signal source is removed, the circuit will eventually lose its energy. How do I make an oscillator out of such an LC circuit that self-starts (that is, I can simulate in LTSPICE which doesn't take into account external noise coming into an oscillator circuit, which is required for some oscillator designs)? I've looked at LC oscillator circuit types like the Hartley oscillator, but I don't see how this can self start in theory under ideal conditions. --=20 http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist .