> http://dl.dropbox.com/u/13600361/BAT%2BMOS.png thanks! As I see it this uses the FET to conduct in revers mode (D is positive=20 with regards to S), correct? I don't see information (RDson figures) for=20 this mode in the datasheets that I looked in. Is it safe to assume that=20 the D and S behave symmetrical? R72 keeps the gate low when there is no +5V, which makes the FET=20 conduct. When +5V is available, the gate is more positive than D or S,=20 so the FET is open. But what is R68 for? It halves the gate voltage in the battery-only=20 mode, which seems a bad idea? --=20 Wouter van Ooijen -- ------------------------------------------- Van Ooijen Technische Informatica: www.voti.nl consultancy, development, PICmicro products docent Hogeschool van Utrecht: www.voti.nl/hvu C++ on uC blog: http://www.voti.nl/erblog --=20 http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist .