> 2012/3/1 Ruben J=F6nsson <maxruben@rjjournal.net>
>=20
> > I would have thought that the debugger could watch the
> > stack to find out where to put a break in order to step out of a functi=
on.
> >
>=20
> Maybe this is what you can do manually if step-out does not work - maybe
> not very convenient but if there no better way...
>=20
> Can you see the call-stack, does that work correctly?
>=20
> Tamas

Actually it is easier than that - Just go to the end curly brace for the=20
function, right click and select "Run To Cursor".

/Ruben
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D
Ruben J=F6nsson
AB Liros Electronic
Box 9124, 200 39 Malm=F6, Sweden
TEL INT +46 40142078
FAX INT +46 40947388
ruben@pp.sbbs.se
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
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--=20
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