Hi =A0all,

I am testing pic32 and something simple I am having hard time to understand=
..
I have 2 leds connected to G12 and G14 when I use test1 code LED1 never tun=
s on.
test2 and test3 is ok. my question is why test1 is not working. G12 and G13=
 are digital I/O.
if i use debugger step over it works.

test1:
LED1 =3D 1;
LED2 =A0=3D 0;=A0
delay;
LED1 =3D0;
LED2=3D1;
delay



test2:
if I use & and | logic it works

LED1 | =3D 1;
LED2 =A0& =3D 0;=A0
delay;
LED1 &=3D0;
LED2 |=3D1;
delay

test3:
if I use LATGSET and LATGCLR it works

Since G12 and G14 are not analog pins and I do not have external capacitor =
I do not think this is Read modify write issue.
my question is do you know why test1 =A0LED1 stays off when running.

here is the code.

while(1)
{
 =A0int short_delay;
 =A0uint8_t returnStatus1,returnStatus2; =A0 =A0 // to test
=A0 =A0 =A0=A0
=A0// =A0 =A0 led_d7_green &=3D 0;
=A0// =A0 =A0 led_d8_green |=3D 1;

=A0// =A0 =A0 led_d7_green =3D 0;
=A0// =A0 =A0 led_d8_green =3D 1;

=A0 =A0 =A0 LATGCLR =3D 0x5000; =A0 // 0b0101000000000000; =A0 =A0 =A0
=A0 =A0 =A0 LATGSET =3D 0x1000; =A0 // 0b0001000000000000;

=A0 =A0 =A0 short_delay =3D 1000*1000; =A0 =A0 // create short delay
=A0 =A0 =A0 while(short_delay--){};

=A0// =A0 =A0 led_d7_green |=3D 1;
=A0// =A0 =A0 led_d8_green &=3D 0;
=A0
=A0// =A0 =A0 led_d7_green =3D 1;
=A0// =A0 =A0 led_d8_green =3D 0;
=A0
=A0 =A0 =A0 LATGCLR =3D 0x5000; =A0 // 0b0101000000000000; =A0=A0
=A0 =A0 =A0 LATGSET =3D 0x4000; =A0 // 0b0100000000000000; =A0=A0
=A0 =A0 =A0=A0
=A0 =A0 =A0 short_delay =3D 1000*1000; =A0 =A0 // create short delay
 =A0while(short_delay--){};

=A0 =A0 }

thanks=A0

Andre
--=20
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