Em 10-01-2012 12:34, alan smith escreveu:
> I'm not sure whats wrong..most likely its how I wired it up
>
> Panasonic AQV252  http://search.digikey.com/us/en/products/AQV252G/255-17=
91-5-ND/571631
>
> 5V system, using a 750ohm resistor to drive the LED in it, and I have ver=
ified the signal is driving on and off
>
> I'm switching 12VDC @1.2A inductive load (solenoid)
>
>
> pins 4/6 are output?  pin 5 is +12V?
>
> Or did I misinterpret the datasheet?
>
>   =20
Do you see the wiring diagrams for it?

For an AC or DC load you can use 4/6 as output, with 4 on +12V, 6 on=20
solenoid and other end of solenoid on ground. Or vice-versa, 6 on +12=20
and 4 on solenoid.

For DC load, you can use both mosfets in paralel with 4 and 6 on=20
solenoid and 5 on ground.

Or, for DC load, you can use 4 OR 6 conected on solenoid and 5 on ground.

The minimal current on led is 5mA, and the 750ohm resistor is OK.


Vinicius
--=20
http://www.piclist.com PIC/SX FAQ & list archive
View/change your membership options at
http://mailman.mit.edu/mailman/listinfo/piclist
.