At 09:34 AM 10/01/2012, you wrote:
>I'm not sure whats wrong..most likely its how I wired it up
>
>Panasonic=20
>AQV252  http://search.digikey.com/us/en/products/AQV252G/255-1791-5-ND/571=
631
>
>5V system, using a 750ohm resistor to drive the LED in it, and I=20
>have verified the signal is driving on and off
>
>I'm switching 12VDC @1.2A inductive load (solenoid)
>
>
>pins 4/6 are output?  pin 5 is +12V?
>
>Or did I misinterpret the datasheet?


Normally, particularly for AC, you would leave pin 5 open and use 4=20
and 6 as the switch.

Say pin 4 to +12

Pin 6 to relay coil (and catch diode)
Ground to other side of relay coil (and other side of catch diode).
Pin 5 (open).

This should be a better way:-

You should be able to reduce the switch voltage drop to 1/4 by=20
connecting 4 & 6 to
+12 and taking the output from pin 5

See below (view in fixed-width font)

                                                       +12
           .-----------------------------.              |
           |                             |              |
       1   |                             |  6           |
        o--|-----+           +--+--------|---o----------+
           |     |           |  |        |              |
           |     |           |  |        |              |
           |     |        ||-+  |        |              |
           |     |        ||<-  -        |              |
           |     |      +-||-+  ^        |              |
           |     V      |    |  |        |              |
           |     -      |    |  |        |  5           |
           |     |      |    +--+--------|---o------+   |
           |     |      |    |  |        |          |   |
           |     |      +-||-+  V        |          |   |
           |     |        ||<-  -        |          |   |
           |     |        ||-+  |        |          |   |
           |     |           |  |        |          |   |
        2  |     |           |  |        |  4       |   |
        o--|-----+           +--+--------|---o------|---+
        |  |                             |          |
       .-. '-----------------------------'          |
       | |                                          |
       | | 750                                      |
       '-'                                          |     \
        |                                         +-+--+ o o
      Drive                                       |     )|
                                                  -     )|
                                                  ^    _)|
                                                  |    |
                                                  +----+
                                                       |
                                                      =3D=3D=3D
                                                      GND


Your drive current with a 750 ohm resistor should be adequate.

Best regards, =20

--=20
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