Hello,

analogously to [division] computing the quotient by counting how many times=
 you
can subtract the divisor, you can compute the square root of a number count=
ing
how many times you can subtract sequential odd numbers (1,3,5,7,9,=85).

[ try it -- it works!]. e.g. 25 -1-3-5-7-9 =3D 0

OK, but can someone explain me *why* it works? :-)

Thanks,
Mario

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