On Wed, Nov 16, 2011 at 8:21 AM, Kerry Wentworth
<kwentworth@skunkworksnh.com> wrote:
> Think of it this way:
>
> Assume you have a sine wave with a period of 360 uS at 2V p-p.
> 30 degrees after a 0 crossing, the voltage will be .5V. =A0At 45 degrees
> it will be .707V, and at 60 degrees it will be .866V. =A0This is the
> definition of a sin wave.
> You can break it down further, and say that, for any 2 points (T1 and
> T2), the voltage at T2 would be
> V2 =3D sin(T2) * (V1 / sin(T1))
> If you have a different value of V2, then you don't have a sin wave,
> even if it LOOKS like a sin wave.

THANKS! That makes a lot of sense. Finally clicks.

Also, I found this to be very useful: Demo 1: Time Domain vs.
Frequency Domain of a Sinusoid
http://library.wolfram.com/infocenter/Demos/7774/

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