Jim ,
Thank you for your reply.
But do you think that I can also use an internal oscilator instead?
I successfully programmed ( into normal PIC16F628A) this code

  #include "P16F628A.INC"  ; Include header file=20
   __CONFIG   _CP_OFF & _LVP_OFF & _BOREN_OFF & _MCLRE_ON & _WDT_OFF &=20
_PWRTE_ON & _INTOSC_OSC_NOCLKOUT=20

		org 10
		movlw	0x07
		movwf	CMCON
		bsf STATUS,RP0		;bank1
		BCF TRISA,2
		bcf STATUS,RP0		;bank0
		BSF PORTA,2
		END

As you can see it uses internal oscilator and it works in normal PIC16F628A=
 / 648A
but still it does not work in PIC16F648A - ICD, no debugging possible.
Must I use external oscilator with PIC16F648A - ICD or also internal oscila=
tor must work?
Thanks again
L


> Let me try this again.
>=20
> PGC and PGD are RB6 and RB7 respectively.  In your schematic you show the
> PGC and PGD pins going to the OSC1 and OSC2 pins.
> This is why there is no ICD functionality with your circuit.
>=20
> If you connect the ICD pins to OSC1 and 2, you effectively disable the
> oscillator.
>=20
> Try moving the ICD PGC and PGD pins to RB6 and RB7.  You should be able t=
o
> use the ICD then.
>=20
> Regards,
>=20
> Jim
>=20
> -----Original Message-----
> From: piclist-bounces@mit.edu [mailto:piclist-bounces@mit.edu] On Behalf =
Of
> jana1972@centrum.cz
> Sent: Saturday, November 05, 2011 9:45 AM
> To: Microcontroller discussion list - Public.
> Subject: Re: [PIC] IS this faulty?
>=20
> Thanks ALL who replied.
> I do use capacitors in the schematic.
> Please see the schematic here
> http://www.dilynamobily.cz/Media/Uploaded/Normal/Problem.jpg
> ( the link is case sensitive)
>=20
> My problem is that I can not debug any program using PIC16f648A - ICD=20
>=20
> Please check and let me  know if you can see any problem
> Thanks
> L.
>=20
>=20
> > OK, whatever.
> >=20
> > We don't know for sure if there are any capacitors or not.
> > And if not, isn't it a possible "problem" ?
> > I think it is.
> >=20
> >=20
> > jim wrote 2011-11-05 14:53:
> > >
> > > The main reason for the capacitors in a crystal circuit is to provide=
 an
> > > intentional imbalance between the input of the oscillator and output =
pin
> of
> > > the oscillator so that when power is applied, the imbalance causess
> current
> > > to flow, and thereby guarantees the oscillator will start oscillating=
..
> > >
> > > Jim
> > >
> > > -----Original Message-----
> > > From: piclist-bounces@mit.edu [mailto:piclist-bounces@mit.edu] On Beh=
alf
> Of
> > > Isaac Marino Bavaresco
> > > Sent: Saturday, November 05, 2011 7:45 AM
> > > To: Microcontroller discussion list - Public.
> > > Subject: Re: [PIC] IS this faulty?
> > >
> > > Em 5/11/2011 10:57, Jan-Erik Soderholm escreveu:
> > >>>> I *think* that the header is useless without a target circuit.
> > >>> But what is the smallest target circuit?I thought adding only cryst=
al
> is
> > >>> OK for starting debugging
> > >> Right, but a crystal is useless without capacitors. And it is
> > >> a bit unclear how the header is powered.
> > >
> > >
> > > Not exactly. It may become unstable, or not to oscillate at all, but =
it
> may.
> > >
> > >
> > >>> Sorry, I have just only  started with microchips  - so a lot  of ne=
w
> > >>> knowledge for me to learn.
> > >> It's not about learing PICs, it's about telling everything and
> > >> not hiding details. :-)
> > >
> > >
> > > By my experience with teaching newbies in electronics and
> > > microcontrollers, it takes time to notice that there's missing
> information.
> > > Because of this, I generally take it easy with them.
> > >
> > >
> > > Isaac
> > >
> > --=20
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> > View/change your membership options at
> > http://mailman.mit.edu/mailman/listinfo/piclist
>=20
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