Hi all, a 2.2uF capacitor charged to 400V discharges in 20uS: what is the formula to calculate the average discharge current? Huge precision is not necessary= , it's just to size appropriately a MOSFET/BJT switch. Thank You very much, Mario PS: I wanna play in the game too! Here's my attempt, maybe correct, maybe n= ot: I'm using two formulas. The first is: Coulomb =3D Farad * Volt thus I get 0.00088 Coulomb inside that charged capacitor. Second formula: Ampere =3D Coulomb / second thus, if I'm not wrong, the right answer should be: 44 Ampere Am I right or wrong? If I'm right, then (since this is a pulse application) I need a switch whic= h can handle peak currents of more than 44A (say 60A to be safe). Did I do my calculation correctly? I'm 100% self-taught *blush* :o Cheers, Mario --=20 http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist .