I don't expect anything, the scheme I gave is for pointing out the
problem as simple as possible. Problem is even if I don't push BTN1 it
executes the contents of if loop there.

On Mon, Oct 24, 2011 at 8:25 PM, Geo <buggiesmith@gmail.com> wrote:
> Yigit Turgut wrote:
>> the code is as following already, forgot to add sorry;
>>
>> sbit BTN1 at RB1_bit;
>> sbit PROT at RB2_bit;
>> sbit =A0TEST at RB3_bit;
>>
>> void main() {
>>
>> TRISB =3D =A000001110;
>> PORTB =3D 00001010;
>> PROT =3D 0;
>>
>> while(1){
>> if( BTN1 =3D=3D =A00){
>> PROT =3D ~PROT } =A0}
>>
> What do you expect to happen when BTN1 goes back to =3D=3D1 ?
>
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