At 12:11 AM 9/17/2011, Oli Glaser wrote:
>On 17/09/2011 02:38, V G wrote:
> > 1. How do you calculate the impedance of a capacitor at a particular
> > fequency?
>
>1/(2pi * C * f)
>
>e.g for a 100nF capacitor at 60Hz:
>
>1/(2pi * 100e-9 * 60) =3D 26.525k

Yep.  Then note that there are two capacitors that bridge the=20
isolation boundary - treat them as being in parallel.  Thus my=20
statement of ~13k at 60Hz.

dwayne

--=20
Dwayne Reid   <dwayner@planet.eon.net>
Trinity Electronics Systems Ltd    Edmonton, AB, CANADA
(780) 489-3199 voice          (780) 487-6397 fax
www.trinity-electronics.com
Custom Electronics Design and Manufacturing

--=20
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