> The trouble is, you don't know the center point until you get the=20
> average, and need the center point to to get the average

What I intended by 'arbitrary' was any centre point chosen. 0 deg
for the OP as he describes it

So if you go back to the OP's original example, with 0/360 degrees
as the reference point and 5 samples

358 359 0 1 2

(-2 -1 0 +1 +2) / 5  =3D 0 wrt 0ref

If the two waves were completely out of phase

(+178 +179 +180 +181 +182) / 5 =3D 180 wrt 0ref

My original idea was to find the relative magnitude of the value, so
that you aren't finding (+358 +359 +0 +1 +2) / 5 + 0ref, which
would give the result 144. At some point the value must be treated
as relatively negative for calculations

Hence if you use 0 as the reference and 180 as the negativity pivot,

(-2 -1 0 +181 +182) =3D 180 wrt 0ref WITHOUT a division

If the values were

177 176 182 183 181, the average is 179.8

-3 -4 +2 +3 +1 =3D -1 wrt 180

-1 / 5 =3D -0.2 =3D> +180 =3D 179.8 wrt 0

Joe
--=20
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