Em 13/5/2011 21:36, enkitec@gmail.com escreveu: > The correct conclusion should be: he could'n get it to work. > > Mark Jordan The math is simple: To electrolyze one mol of electrons, you need one Faraday of charge (96400 Coulomb). One mol of water equals 18g, and each molecule needs two electrons ( one for each H), so for electrolyzing 18g of water you need two Faradays of charge (192800 Coulombs). 192800C / 1800s =3D 107A (that is, to electrolyze 18g of water it is necessary to apply 107 Amperes during 1/2 hour) Do the rest of the math and you will see that there is no way of getting all that energy back burning just 18g of O2+H2.. Isaac --=20 http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist .