Andre,

For *each* cylinder, you will get one pulse every two crankshaft =20
rotations.  So at 8000 rpm, you will get 8000/2 =3D 4000 pulses per =20
minute, or 66.67 pulses per second (Hz).  For four cylinders you will =20
get 266.67 Hz at 8000 rpm.

Cheers,
-Neil.



Quoting Andre Abelian <abelian.andre@yahoo.com>:

> Jack,
>
> sorry yes I mean beetle.
> this means 8000rpm/60 =3D133hz/2 =3D 66.6 this is what I should see per c=
ylinder
> right?
> and by looking at main sensor side (or coil side) I should see 66.6*4=3D2=
66.4hz
> now I am totally lost... are you sure it divided by 2?
>
> thanks
>
> AA
>
>
>
>
> ________________________________
> From: John Gardner <goflo3@gmail.com>
> To: Microcontroller discussion list - Public. <piclist@MIT.EDU>
> Sent: Mon, March 7, 2011 9:39:08 AM
> Subject: Re: [EE]: VW engine RPM question
>
> Hi Andre -
>
> "VW Battle engine"  =3D "VW Beetle engine?"...
>
> If it's a 4-cycle engine, and the rotor you refer to
> is the distributor rotor, it turns at 1/2 crank speed.
>
> Jack
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