At 02:08 AM 2/28/2011, you wrote:
> > It does work with the full year, you just have to get the order of stuf=
f
> > right. I tried it with your first example and got 319 - for N3:
> >
> > 1 + ((2010 - 4 * (floor(2010 / 4) + 2) / 3)
> > =3D 1 + ((2010 - 4 * (502) + 2) / 3)
> > =3D 1 + ((2010 - 2008 + 2) / 3)
> > =3D 1 + (floor(4/3))
> > =3D 2
> >
> > N =3D 336 - (1 * 2) + 15 - 30 =3D 319
>
>Well, I really did think I had the operator precedence correct
>
>( ) * / + -
>
>By "my" order
>
>(floor(2010 / 4)+2) is worked first =3D 504

No, the multiplication operator has precedence over addition (or subtractio=
n,
which are equal precedence), so we have to multiply by 4 before adding the =
2
(and the year).

http://en.wikipedia.org/wiki/Order_of_operations

The order of calculation might be clearer if they had grouped the '2' and t=
he
year, but I think they were trying to make it bit easier to understand what=
 is
going on.. which is always good.. for example, one can easily see that this
algorithm has a Y2K1 problem.

Best regards,

Spehro Pefhany --"it's the network..."            "The Journey is the rewar=
d"
speff@interlog.com             Info for manufacturers: http://www.trexon.co=
m
Embedded software/hardware/analog  Info for designers:  http://www.speff.co=
m



--=20
http://www.piclist.com PIC/SX FAQ & list archive
View/change your membership options at
http://mailman.mit.edu/mailman/listinfo/piclist
.