On 28/02/2011 04:25, IVP wrote:
>> Here's the problem, you're in the wrong millennium! year !=3D 10 ; year =
=3D
>> 2010
>>
>> Now it will work out to 319. (N3 =3D 2)
> I tried it that way first
>
> (1 + INT(2010 - (4 * (INT(2010/4) + 2)/3)))
>
> Working from inside out
>
> INT(2010/4) + 2 =3D 504
>
> * 4 =3D 2016
>
> /3 =3D 672
>
> N3 =3D 1 + INT(2010 - 672) =3D 1339
>
> If N1 =3D 336 and N2 =3D 1
>
> N =3D 336 - (1 * 1339) + 15 - 30 =3D - 1005
>
> ? (I think)
>
> Joe
>

Hi Joe,

It does work with the full year, you just have to get the order of stuff=20
right. I tried it with your first example and got 319 - for N3:
1 + ((2010 - 4 * (floor(2010 / 4) + 2) / 3)
=3D 1 + ((2010 - 4 * (502) + 2) / 3)
=3D 1 + ((2010 - 2008 + 2) / 3)
=3D 1 + (floor(4/3))
=3D 2

N =3D 336 - (1 * 2) + 15 - 30 =3D 319

There is an example here:
http://williams.best.vwh.net/sunrise_sunset_example.htm








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