> Here's the problem, you're in the wrong millennium! year !=3D 10 ; year =
=3D=20
> 2010
>
> Now it will work out to 319. (N3 =3D 2)

I tried it that way first

(1 + INT(2010 - (4 * (INT(2010/4) + 2)/3)))

Working from inside out

INT(2010/4) + 2 =3D 504

* 4 =3D 2016

/3 =3D 672

N3 =3D 1 + INT(2010 - 672) =3D 1339

If N1 =3D 336 and N2 =3D 1

N =3D 336 - (1 * 1339) + 15 - 30 =3D - 1005

? (I think)

Joe=20

--=20
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