On 29/01/2011 13:05, Gerhard Fiedler wrote: > Without resulting average momentum at > the bottom of the box, there is no force, and hence, I'm convinced that > if you make the box big enough, what you'll have is a box that has the > same weight with and without a plane flying in it, Newton and everything > considered. This is incorrect. All very interesting though, I enjoyed the exchange here... Anyway, I went back to see roughly where it started and the above looked=20 about right. Thought I'd have a quick go at changing Gerhards mind.. I don't think it matters too much about the exact mechanism of flight,=20 as this makes no difference to the bigger picture anyway (the "box"=20 feels the same force either way - essentially the atmosphere will get=20 heavier when the plane leaves the ground) With the above statement - essentially what you are saying is that it is=20 possible to place an object (plane, heavier than air) into a closed=20 system (box, filled with air) and have it make no difference to the=20 weight. In this case, if the box is initially weighed with the plane=20 before take off - does it get lighter after the plane takes off? Where=20 does the weight go? Will this be the same with a box filled with water and a heavier than=20 water craft keeping itself afloat? If you take all the air inside the box, and add the plane - regardless=20 of how big the box is, or what the plane is doing, ask this question: Is=20 the total weight more than before the plane was added? Is it possible to change a closed (and steady state) systems weight? =20 (assuming no change in gravity, nor observing from speeds close to light) --=20 http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist .