V G wrote:
> * The plastic bag that the inductor came with says that it's a "power"
> inductor rated at 1/2 W with a resistance of 0.3 ohms. I then
> measured the resistance with my multimeter and found it to be 0.7
> ohms, but that could be wrong?

Yes, if the inductor is of questionable origin or from a questional
supplier.  More likely though is that your ohm meter isn't that good below =
1
ohm.  To check, short the leads together and see what it says.  Maybe it as
a option to zero it with the leads shorted.

> * At 0.3 ohms, (I^2)*R < 0.5 W, I would get around 1.29 A max.

Yes, that seems to add up.

> What
> are the effects of pushing more than 1.29 A through this thing?

It will get hotter than it's supposed to.  At first it will probably just
not live up to datasheet specs.  If the overheat is significant, it will
fail.

> * I don't plan on drawing more than 1 A, so the peak current through
> the inductor should be less than the waveform shown on page 26, and I
> should be good to go?

I don't know what's on page 26, but you've already shown that 1.29A is safe
in terms of total dissipation.  That tells you the upper limit of the RMS
current.  The other parameter you need is the saturation current.  That is
the instantaneous upper current limit for most normal circuits where the
inductor is expected to remain acting like a inductor.


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