Em 12/7/2010 17:26, Steve Smith escreveu:
> Just a simple matter of rectification as I assume you mean 12v DC. =

>
> Therefore 2000 / 12 v =3D 166A X 0.8v(x2) =3D or 266w loss in the rectifi=
cation
> diodes.
>
> This compares directly to nothing if you use 240v at 8.3 A AC... you will
> save 13% of the lost energy that it takes to rectify the low voltage
>
> Enjoy
>
> Steve


If his alternator is 3-phase he will need 6 diodes and the current will
pass through 2 diodes in series, so double the loss.

He could use synchronous rectification to reduce the loss, but it would
require a lot of very big MOSFETS.

And don't forget the ripple (around 13% for a 3-phase system). I think
that filtering has little use at these current levels.


Isaac

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