Michael Watterson wrote:
> Lucas Tanure wrote:
>> Yes, the system will be powered by the battery. And I want to know
>> if the battery is on 20% of the power. It's a 5.0v battery.
>
> you need a stable reference
>
> The simplest scheme is to have a comparator reference and  detect  1V
> or  a fraction of 1V  via resistor divider from the 5V
> The reference volts  must be stable as the battery discharges. But I
> perhaps misunderstand, maybe you don't mean 20% of volts

He clearly said 20% of "power", which makes little sense either, but is
certainly not volts.  Power is the instataneous energy transferred per time.
Sortof like the concept of "cold cranking amps", but of course not exactly
since the units are different.

This guy sounds like he's not a native english speaker, so I think he
probably meant "energy" or "capacity", not power.


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