On 26/05/2010 20:14, Xiao Xu wrote: > PIC 84 microprocessors have instruction sets that are 14 bits long, > but there are only 35 instructions. > So wouldn't it be more efficient to make each the instruction sets 6 > bits, then you can represent 2^6=64 instructions, which is more than > you need. > What's the point of the 8 extra bits? The arguments are part of the instruction, therefore more bits are needed than just the actual opcode itself. David -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist