Bringing back my post, if You don't mind. :P

At 17.57 2010.04.29, you wrote:
[..]
>In my 2-stroke enduro motorbike I have a single stator with six windings, one
>is used for the battery-less CDI, and then other five for lights, etc.. The CDI
>one has a resistance of 15 ohms: question number one.. if I measure 
>e.g. 60V RMS, should I expect it to give ~4A of short circuit current? (I=V/R)

I have found that with a resistive 40 ohm load the voltage accross the stator is
halved (versus no load): thus that's the correct load to extract as much energy
as possible from it, I reckon. I.e. the stator has an effective "source" impedance
of 40 ohm (a resistance of 15 ohm plus whatever comes from its own inductance).

But I could do the test only at low RPM.

How will the source impedance change at higher RPM's? Series inductance means
that at higher frequences the impedance should increase further, thus the load
resistance should increase too, to extract full power, right?

Is this the reason why a stator running at twice the speed doesn't produce,
under load, twice the voltage. I reckon this because the magnetic coupling should
not change with speed. Correct?


>can I use the
>stator itself as an inductor, shorting it directly with a MOSFET, and then
>expecting it to produce a high tension peak useful to charge (through a diode)
>the CDI capacitor? I.e. a kind of primitive boost converter 8)

The above was unanswered.. I hope some of You can give it a shoot this time. 8)

Cheers,
Mario

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