Gerhard Fiedler wrote: >>>> Out = Gain(PosIn - NegIn) >>> >>> Well, no, it doesn't. If it did, several common circuits wouldn't >>> work as intended (including the Schmitt-Trigger you used in your >>> example), >> >> No, the above equation shows what the opamp does in all cases, even >> when used in a circuit with hysteresis. I did leave out clipping at >> the power rails, but thought it was understood a opamp can't generate >> a voltage outside the range it is given. > > You say "it was understood". If everything that is understood is > really understood, what was your point with your criticism in your > previous message? :) I am now totally lost as to what your point is, except possibly just to argue. When you said "no, it doesn't" above, were you referring to my leaving out that the output will be clipped to the supply range, or something else? ******************************************************************** Embed Inc, Littleton Massachusetts, http://www.embedinc.com/products (978) 742-9014. Gold level PIC consultants since 2000. -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist