> Take the 5mA case. Input power is 3.8V * 6.96mA = 26.4mw
>                    Output power is 5V * 5mA = 25mW
> 
> Efficiency = output power/input power  = 94.7%

You know, I never even thought to compare wattages, yet I've
seen that as the answer to so many other people's queries !! ;-)

Thanks
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