On Sat, Apr 17, 2010 at 10:39:56AM -0400, Byron Jeff wrote:
> On Fri, Apr 16, 2010 at 09:51:28AM -0400, Isaac Marino Bavaresco wrote:
> > Em 16/4/2010 11:22, Byron Jeff escreveu:
> > > On Thu, Apr 15, 2010 at 11:23:21PM -0400, Justin Richards wrote:
> > >   

Some snippage....

> > > Presuming that new1 is a struct. But to reiterate you can get both space
> > > and a pointer to that space simply be declaring a single element array.
> > > i.e.
> > >
> > > Temp_t new1[1];
> > >
> > > Now new1 is a pointer to the allocated first element. No need to track two
> > > different names.
> > >   
> > 
> > You just replaced one annoyance by another, now you need to use
> > "new1[0].Var00" and so on.
> 
> No you don't. remember that the name new1 represents a pointer to a
> structure. And fortunately C has an operator that takes a pointer to a
> structure and accesses fields in the structure that the pointer points to.
> It's called the arrow operator (->). So the above would be written:
> 
> new1->Var00
> 
> And in my system, almost without exception structure access occurs through
> a pointer, so the usage of the arrow operator is consistent both in a out
> of functions with structs as parameters. So instead of:
> 
> //////////////////////////////////////////////////
> void myfunc(Temp_p testme)
> {
>    test->Var00 = 14;
> }
> 
> void main()
> {
>    Temp_t myvar;
> 
>    myfunc(&myvar)
>    printf("myvar.Var00 =  %d\n",myvar.Var00);
> }
> 
> //////////////////////////////////////////////////
> I would use:
> 
> //////////////////////////////////////////////////
> void myfunc(Temp_p testme)
> {
>    test->Var00 = 14;
> }
> 
> void main()
> {
>    Temp_t myvar[0];

This is a mistake, it of course should be:

     Temp_t myvar[1];

I think I saw the 0 in the index access above and unconsciously copied it.

BAJ
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