I think you would be probably better off starting with something veru simple, like a crystal radio (http://en.wikipedia.org/wiki/Crystal_radio). The AM demodulator is a simple germanium diode -- in extreme case you do not even use anything else, only the diode, a long antenna and a head phone. Then everything else is just an add-on or plug-in if you like it that way. So you can add as an add-on a resonant for tuning to a specific station, then a simple audio amp, later on an RF amp so that finally you get a very basic radio receiver. Tamas On Wed, Mar 31, 2010 at 7:27 AM, solarwind wrote: > I've been very interested in electrical engineering and radio > recently. I've been trying to learn how radio waves tie into > electrical engineering. How do we create them? How do we receive them? > I've read the howstuffworks article as well as some Wikipedia pages on > the matter, but still do not know exactly how they "work". > > For example, a very simple 1 MHz AM transmitter is described here: > http://sci-toys.com/scitoys/scitoys/radio/am_transmitter.html > > I am referring to the image here: > http://sci-toys.com/scitoys/scitoys/radio/xmitter_schematic.gif > > I understand that the top left pin of the crystal oscillator is the > input for some voltage. So assuming that I provide a steady +5 volts > on that pin, what will I see on the output pin (top right)? Will I see > a 1 MHz wave with a peak voltage of +5 volts? Or will it have an RMS > voltage of 5 volts? > > How is the radio wave generated in this case? If I stick an > appropriately sized antenna on the output pin, how is the radio wave > generated? Why is it generated? Is it because of the oscillating > potential difference across the output pin and ground? > > What governs the output power of the radio wave? How do we generate a > more "powerful" signal? Assuming the photon theory of electromagnetic > radiation (if that is the correct theory to use here), does the output > power refer to the number of photons emitted/time? If so, how do we > increase the power? And why are the photons emitted in the first > place? > > On the receiving end, assuming a properly sized antenna, how is the > radio wave "received"? When a radio wave strikes the antenna, what > happens? If I were to have a long, straight piece of wire and clip two > terminals of a sensitive oscilloscope to each end of that wire, will I > be able to see the wave (assuming a powerful enough transmitter)? If > not, why not? > > I know bits and pieces of things but I'm still not able to see the big > picture here. I can only understand this stuff if I know the > fundamentals on a very low level. > > I'm really trying to learn this stuff, and I have searched in several > books and on the Internet, but it is proving to be a difficult task to > find this information. I know you guys are the best people to ask. So > here I am. > -- > http://www.piclist.com PIC/SX FAQ & list archive > View/change your membership options at > http://mailman.mit.edu/mailman/listinfo/piclist > -- int main() { char *a,*s,*q; printf(s="int main() { char *a,*s,*q; printf(s=%s%s%s, q=%s%s%s%s,s,q,q,a=%s%s%s%s,q,q,q,a,a,q); }", q="\"",s,q,q,a="\\",q,q,q,a,a,q); } -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist