Olin Lathrop wrote: > Philip Pemberton wrote: >> I'm probably being really thick here, > > Careful, you may not be allowed to say that anymore for fear you'd get upset > and say bad things to yourself ;-) Oh dear, I just insulted myself! Call the Thought Police! Think of the children, won't someone *please* think of the children?! :) > No, the FET should be able to operate over the full 9V battery range, else > someone chose the wrong FET. This schematic smells a bit like someone was > using rules of thumb and didn't stop to think what they were really for and > when they apply. You often see gate resistors like R10 in fast switching > applications when the drain dV/dt is expected to be large and the circuit > can switch the gate quickly. In this case the FET is being run in linear > mode and the opamp is likely not that fast, so that reason doesn't apply. 700kHz bandwidth at unity gain with Vcc=+-15V, according to the TI datasheet, or 1MHz according to National Semiconductor. Interesting that the output driver stage of the '358 has a series resistor in the pull-up (NPN) path, but not in the pull-down (PNP) path... Hm. > The FET gate does look like a capacitive load, and many opamps aren't stable > with those. Some series resistance can keep the opamp stable in such cases. > I haven't looked at the LM358 datasheet, but 10 ohms sounds low for that > purpose. Oh, here we go (copied from the NSC datasheet, page 8): > For ac applications, where the load is capacitively coupled to > the output of the amplifier, a resistor should be used, from > the output of the amplifier to ground to increase the class A > bias current and prevent crossover distortion. Where the > load is directly coupled, as in dc applications, there is no > crossover distortion. > > Capacitive loads which are applied directly to the output of > the amplifier reduce the loop stability margin. Values of 50 > pF can be accomodated using the worst-case non-inverting > unity gain connection. Large closed loop gains or resistive > isolation should be used if larger load capacitance must be > driven by the amplifier. So it's plausible that R{4,10} are there to stop the amp going into oscillation due to the FET's gate capacitance (the FET presents a worst-case 4nF capacitive load -- typical rating is about 2nF). As for the two output-to-inverting-input resistors (R13 and R14), the first paragraph would seem to apply, but the output isn't capacitively coupled, so maybe not. There are a few application circuits kicking around the 'net, but curiously most of them appear to use BJTs. Based on the calculations I did, a FET would run cooler in this application at a cost of losing the ESD resistance of BJTs... Although I can't say I've ever (knowingly) blown a FET up with ESD, usually around here they die of catastrophic overvoltage or overheating (fizz, fizz, melt, melt). -- Phil. piclist@philpem.me.uk http://www.philpem.me.uk/ -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist