2010/2/20 MCH <mch@nb.net>:
> Can someone explain that command to me? (MOVLW '0'-1)
>
> I know what MOVLW is, and I understand the (default radix) of '0' (in
> which case I guess the radix doesn't matter anyway since it's 0), but
> I'm stumped by the "-1" on the end. I don't see any provision for that
> in the docs. What does that do?
>
> Thanks,
> Joe M.
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No.  '0' is not zero.  It's "character 0", which has ascii value of
0x30, or 48 in decimal. The statement you mentioned is equavalent to
the following:

MOVLW 0x2F
MOVLW .47


Hope this helps,

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